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What is the value of b2 - 4ac for the following equation 5x2 + 7x = 6

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5x^2+7x-6 =0 a=5 b=7 c=-6 b^2-4ac = 7^2 -4(5)(-6) = 49+120 = 169

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49 + 20 = 69.

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a = 5, b = 7 and c = -6 since the equation is written 5x² + 7x - 6 = 0 = (5x-3)(x+2) so x = 3/5 or x = -2 b² - 4ac = 7² - 4*5*(-6) = 49 + 20*6 = 169 and √169 = 13 -b/2a +/-√(b²-4ac)/2a = -7/10 + 13/10 = 6/10 = 3/5 and -7/10 - 13/10 = -20/10 = -2 Thus 5x² +7x - 6 = 5(x-3/5)(x+2)

            
        

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