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Calculus homework help please

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the position function of a particle is given by s(t) = t^3 - 12t^2 + 45t + 3, where time, t, is in seconds, distance, s, is in meter, and t > 0. find the velocity of the particle when the acceleration is 0

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v(t) = ds/dt v(t) = 3t^2 - 24t + 45 a(t) = dv/dt a(t) = 6t - 24 when a = 0;
t = 4 v = 3(4)^2 - 24(4) + 45 v = -3 m/s

            
        

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