Ask a Question

Basic Logarithm question

0 votes
If I have -log(0.1/x) = .16 , how do I get rid of the log to solve for x?


0 votes

First get rid of the minus sign by negating both sides. log(0.1/x) = -0.16. The opposite of log is raising to a power. If these are base 10 logs, raise 10 to the power of both sides. 0.1/x = 10^(-0.16) = 0.692. Now you can rearrange to solve for x. 0.1 = 0.692x x = 0.1/0.692 = 0.145 Note: Another thing you could have done with the minus sign is bring it inside the log, as n * log(a) = log(a^n). So -1 * log(a) = log(a^-1) = log(1/a). That is, the log of a reciprocal is the negative of the log. In other words -log(0.1/x) = log(x/0.1). Now raise 10 to the power of both sides. log(x/0.1) = 0.16 x/0.1 = 10^0.16 = 1.45 x = 1.45*0.1 = 0.145


Bienvenidos a Sysmaya

Sysmaya le permite ser creativo con tus amigos.
Conectese con Facebook para que pueda comenzar a compartir.

Ahora no, Gracias.

USA Yellow Pages

Pagina Procesada y Actualizada en: 0.042 Segs

shopify stats