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Give the domain of the function.
square root of x+3 over (x+9)(x+3)
and how

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The domain is all possible values of x. Numbers that are immediately excluded: x = -9 x = -3 As either one would make the denominator 0, and division by 0 is not defined. However, if you look at the numerator, you see that any x<-3 is also excluded, since that would mean x + 3 <0, which means its square root is imaginary. So the domain is x<= - 3, which includes the numbers excluded by the denominator.


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