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An isosceles triangle has a perimeter of 2 cm. Find a function that models its area A in terms of the length of its base b.

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Each of the sides other than the base could be written as (1/2)(2 - b) = 1 - (1/2)b. And hence, h = sqrt[(1 - (1/2)b)^2 - b^2] = sqrt[1 - b - (3/4)b^2], so A = (1/2)*b*sqrt[1 - b - (3/4)b^2].


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